We do this by looking for a pair of numbers that have a product equal to the constant on the end of the trinomial and a sum equal to the - 3x - 10 into (x 2)(x - 5) by realizing that 2 * -5 = -10, and 2 -5 = -3. The goal is still the same - split the trinomial into a product of binomials - and we'll still find a lot of the same patterns, but now we'll have to make two slight changes in the process in order to end up with the correct answer.

Let's go ahead and take a look at the example I just mentioned.

So, if I look at the top row of this chart, I have a 2x and -6x.

I need to ask myself what do those things have in common?

It will be the same general idea, but there are a few extra steps to learn. This lesson will be on advanced factoring techniques, so I'm going to assume that you know a few things: first, that factoring is the process of breaking up a number into the things that we can multiply together to get that number.

This means that factoring a quadratic expression is the process of taking a trinomial and turning it into multiplication of two binomials - basically FOIL backwards. Well, the method I just described only works for quadratic trinomials where the - 5x - 3, we're going to be in trouble.Plus, get practice tests, quizzes, and personalized coaching to help you succeed.Try it risk-free Once you get good at factoring quadratics with 1x squared in the front of the expression, it's time to try ones with numbers other than 1.One part stays the same, and that is the fact that we need to find a pair of numbers that will add up to the middle coefficient - in this case, -5. Instead of our two numbers needing to have a product equal to the constant on the end, we now need the product of our pair of numbers to be equal to the constant on the end times the leading coefficient.This was actually true for the easier factoring problems as well, but the leading coefficient was just 1, so multiplying by 1 didn't change what the number was. Find a pair of numbers that has a sum of -5 and a product of -6.Lastly, we need to divide out the greatest common factors from each row and column to find out which binomials exist on the outside of this chart.Looking at the top row, it looks like they both have a 3 and an x. The left column, I see a 3 and an x again, and the right column, they both have a -2 so I can pull that out.Factor 2x We'll start this problem very similarly to the simple factoring problems by looking for two numbers that fit the pattern.The thing is, it's not going to be quite the same pattern.You can test out of the first two years of college and save thousands off your degree.Anyone can earn credit-by-exam regardless of age or education level.

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