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The steps of the Hungarian algorithm can be found here, and an explanation of the Hungarian algorithm based on the example above can be found here.Consider the following problem: Due to neglect, your home is in serious need of repair.It was developed and published in 1955 by Harold Kuhn, who gave the name “Hungarian method” because the algorithm was largely based on the earlier works of two Hungarian mathematicians: Dénes Kőnig and Jenő Egerváry.
All other assignments lead to a larger amount of time required.
The Hungarian algorithm can be used to find this optimal assignment.
The jobs are denoted by J1, J2, J3, and J4, the workers by W1, W2, W3, and W4.
Each worker should perform exactly one job and the objective is to minimize the total time required to perform all jobs.
The assignment problem deals with assigning machines to tasks, workers to jobs, soccer players to positions, and so on.
The goal is to determine the optimum assignment that, for example, minimizes the total cost or maximizes the team effectiveness.However, only rows 1, 3 and 4 have a zero, with row for having 2 of them. We cycle through the rows now, and convert the lowest value in each row to a zero, only if the row doesn’t currently have a zero.After completing step 2 we can see that each row and each column have a zero, which leaves us with the challenge of allocating the appropriate jobs to each contractor.I’m going to be using something called the Hungarian Method.The Hungarian method is a combinatorial optimization algorithm that solves the assignment problem in polynomial time and which anticipated later primal-dual methods.Because each worker has different skills, the time required to perform a job depends on the worker who is assigned to it.The matrix below shows the time required (in minutes) for each combination of a worker and a job.And we might naturally just go with Susan, since she’s giving us the best overall price.However, another solution might be to break down what we need done into individual items.Let’s take a look at how this method could be applied to our current problem: Here, we can see that each column has a zero.However, only rows 1, 3 and 4 have zeros, and row 4 has 2 zeros.